In C, is there a nice way to track the number of elements in an enum? I've seen
enum blah {
FIRST,
SECOND,
THIRD,
LAST
};
But this only works if the items are sequential and start at zero.
From stackoverflow
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Unfortunately, no. There is not.
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I don't believe there is. But what would you do with such a number if they are not sequential, and you don't already have a list of them somewhere? And if they are sequential but start at a different number, you could always do:
enum blah { FIRST = 128, SECOND, THIRD, END }; const int blah_count = END - FIRST;ojblass : can enum types be negative? If so watch out with this one.paxdiablo : FIRST=-2 would still calculate correctly, I think: 1 - (-2) = 3.Brian Campbell : No need to watch out; subtraction works just fine for negative numbers. Pax has it right.ojblass : FIRST = -200, SECOND = -199, THIRD = -198, END = -100. -200 - (-100) = bad newsojblass : One case that works does not a proof make.ojblass : even sequiental that breaksBrian Campbell : I meant sequential as in you only ever set the first value, and let each remaining value increment by default, in sequence. enum blah { FIRST=, SECOND, THIRD, END }; ojblass : like i am saying thought setting the first to -9 and having 3 elements -9 - (-7) = -2. You need an absolute value or something.Brian Campbell : No, you would get FIRST = -9 SECOND = -8 THIRD = -7 END = -6, so you'd have -6 - (-9) = -6 + 9 = 3ojblass : ah yes... duh...Brian Campbell : No problem; an easy mistake to make. -
Well, since enums can't change at run-time, the best thing you can do is:
enum blah { FIRST = 7, SECOND = 15, THIRD = 9, LAST = 12 }; #define blahcount 4 /* counted manually, keep these in sync */But I find it difficult to envisage a situation where that information would come in handy. What exactly are you trying to do?
ojblass : Yes why would you want to do that! -
See this SO question about enums in C++ like in Ada.
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